9405. Professor and balloons

For the holiday, the Professor bought blue, red, and yellow balloons. In total he bought n balloons. There are a yellow and blue balloons together. There are b red and blue balloons together.

How many blue, red and yellow balloons did the Professor buy?

Input. Three positive integers n, a, b.

Output. Print in one line the number of blue, red and yellow balloons that the Professor bought.

Sample input	Sample output
10 6 8	4 4 2

SOLUTION

mathematics

Algorithm analysis

Let the number of blue, red and yellow balls be respectively blue, red and yellow. According to the condition of the problem, it is known that:

· yellow + blue = a (yellow and blue balloons);

· red + blue = b (red and blue balloons);

· blue + red + yellow = n (there are n balloons in total)

From the system of equations, we find the number of balloons of each color:

· red = n – a;

· yellow = n – b;

· blue = a + b – n;

Algorithm realization

Read the input data.

scanf("%d %d %d", &n, &a, &b);

Compute and print the answer.

blue = a + b - n;

red = n - a;

yellow = n - b;

printf("%d %d %d\n", blue, red, yellow);

Java realization

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int n = con.nextInt();

int a = con.nextInt();

int b = con.nextInt();

int blue = a + b - n;

int red = n - a;

int yellow = n - b;

System.out.println(blue + " " + red + " " + yellow);

con.close();

}

}

Python realization

Read the input data.

n, a, b = map(int,input().split())

Compute and print the answer.

blue = a + b - n;

red = n - a;

yellow = n - b;

print(blue, red, yellow);